Suppose $2-p, p, 2-\alpha, \alpha$ are the coefficients of four consecutive terms in the expansion of $(1+x)^n$. Then the value of $p^2-\alpha^2+6\alpha+2p$ equals

  • A
    $4$
  • B
    $10$
  • C
    $8$
  • D
    $6$

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